9m^2-27m+8=0

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Solution for 9m^2-27m+8=0 equation: 



9m^2-27m+8=0

a = 9; b = -27; c = +8;
Δ = b2-4ac
Δ = -272-4·9·8
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-21}{2*9}=\frac{6}{18}
=1/3
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+21}{2*9}=\frac{48}{18}
=2+2/3
$

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